最长回文子序列
最长回文子序列
题目
给定一个序列,找到它的最长回文子序列。在回文子序列中,元素从前往后读和从后往前读是一样的。 子序列是从另一个序列派生出来的序列,删除一些元素或不删除任何元素,而不改变其余元素的顺序。
示例:
输入:"abdbca"
输出:5
解释:最长回文子序列是"abdba"
题解
基础解法
class LPS {
public int findLPSLength(String st) {
return findLPSLengthRecursive(st, 0, st.length()-1);
}
private int findLPSLengthRecursive(String st, int startIndex, int endIndex) {
if(startIndex > endIndex)
return 0;
//有一个元素的序列是一个长度为1的回文序列
if(startIndex == endIndex)
return 1;
//选项1:序列头和尾的元素相同
if(st.charAt(startIndex) == st.charAt(endIndex))
return 2 + findLPSLengthRecursive(st, startIndex+1, endIndex-1);
//选项2: 从开头或结尾跳过一个元素
int c1 = findLPSLengthRecursive(st, startIndex+1, endIndex);
int c2 = findLPSLengthRecursive(st, startIndex, endIndex-1);
return Math.max(c1, c2);
}
public static void main(String[] args) {
LPS lps = new LPS();
System.out.println(lps.findLPSLength("abdbca"));
System.out.println(lps.findLPSLength("cddpd"));
System.out.println(lps.findLPSLength("pqr"));
}
}
class LPS {
findLPSLength(st) {
return this.findLPSLengthRecursive(st, 0, st.length - 1);
}
findLPSLengthRecursive(st, startIndex, endIndex) {
if (startIndex > endIndex) {
return 0;
}
if (startIndex === endIndex) {
return 1;
}
if (st.charAt(startIndex) === st.charAt(endIndex)) {
return 2 + this.findLPSLengthRecursive(st, startIndex + 1, endIndex - 1);
}
const c1 = this.findLPSLengthRecursive(st, startIndex + 1, endIndex);
const c2 = this.findLPSLengthRecursive(st, startIndex, endIndex - 1);
return Math.max(c1, c2);
}
}
const lps = new LPS();
console.log(lps.findLPSLength("abdbca"));
console.log(lps.findLPSLength("cddpd"));
console.log(lps.findLPSLength("pqr"));
class LPS:
def findLPSLength(self, st):
return self.findLPSLengthRecursive(st, 0, len(st) - 1)
def findLPSLengthRecursive(self, st, startIndex, endIndex):
if startIndex > endIndex:
return 0
if startIndex == endIndex:
return 1
if st[startIndex] == st[endIndex]:
return 2 + self.findLPSLengthRecursive(st, startIndex + 1, endIndex - 1)
c1 = self.findLPSLengthRecursive(st, startIndex + 1, endIndex)
c2 = self.findLPSLengthRecursive(st, startIndex, endIndex - 1)
return max(c1, c2)
lps = LPS()
print(lps.findLPSLength("abdbca"))
print(lps.findLPSLength("cddpd"))
print(lps.findLPSLength("pqr"))
package main
import "fmt"
type LPS struct{}
func (lps LPS) findLPSLength(st string) int {
return lps.findLPSLengthRecursive(st, 0, len(st)-1)
}
func (lps LPS) findLPSLengthRecursive(st string, startIndex, endIndex int) int {
if startIndex > endIndex {
return 0
}
if startIndex == endIndex {
return 1
}
if st[startIndex] == st[endIndex] {
return 2 + lps.findLPSLengthRecursive(st, startIndex+1, endIndex-1)
}
c1 := lps.findLPSLengthRecursive(st, startIndex+1, endIndex)
c2 := lps.findLPSLengthRecursive(st, startIndex, endIndex-1)
if c1 > c2 {
return c1
}
return c2
}
func main() {
lps := LPS{}
fmt.Println(lps.findLPSLength("abdbca"))
fmt.Println(lps.findLPSLength("cddpd"))
fmt.Println(lps.findLPSLength("pqr"))
}
自顶向下(备忘录)
class LPS {
public int findLPSLength(String st) {
Integer[][] dp = new Integer[st.length()][st.length()];
return findLPSLengthRecursive(dp, st, 0, st.length()-1);
}
private int findLPSLengthRecursive(Integer[][] dp, String st, int startIndex, int endIndex) {
if(startIndex > endIndex)
return 0;
//有一个元素的序列是一个长度为1的回文序列
if(startIndex == endIndex)
return 1;
if(dp[startIndex][endIndex] == null) {
//选项1:序列头和尾的元素相同
if(st.charAt(startIndex) == st.charAt(endIndex)) {
dp[startIndex][endIndex] = 2 + findLPSLengthRecursive(dp, st, startIndex+1, endIndex-1);
} else {
//选项2: 从开头或结尾跳过一个元素
int c1 = findLPSLengthRecursive(dp, st, startIndex+1, endIndex);
int c2 = findLPSLengthRecursive(dp, st, startIndex, endIndex-1);
dp[startIndex][endIndex] = Math.max(c1, c2);
}
}
return dp[startIndex][endIndex];
}
public static void main(String[] args) {
LPS lps = new LPS();
System.out.println(lps.findLPSLength("abdbca"));
System.out.println(lps.findLPSLength("cddpd"));
System.out.println(lps.findLPSLength("pqr"));
}
}
class LPS {
findLPSLength(st) {
const dp = Array.from({ length: st.length }, () => Array(st.length).fill(null));
return this.findLPSLengthRecursive(dp, st, 0, st.length - 1);
}
findLPSLengthRecursive(dp, st, startIndex, endIndex) {
if (startIndex > endIndex)
return 0;
if (startIndex === endIndex)
return 1;
if (dp[startIndex][endIndex] === null) {
if (st[startIndex] === st[endIndex]) {
dp[startIndex][endIndex] = 2 + this.findLPSLengthRecursive(dp, st, startIndex + 1, endIndex - 1);
} else {
const c1 = this.findLPSLengthRecursive(dp, st, startIndex + 1, endIndex);
const c2 = this.findLPSLengthRecursive(dp, st, startIndex, endIndex - 1);
dp[startIndex][endIndex] = Math.max(c1, c2);
}
}
return dp[startIndex][endIndex];
}
}
const lps = new LPS();
console.log(lps.findLPSLength("abdbca"));
console.log(lps.findLPSLength("cddpd"));
console.log(lps.findLPSLength("pqr"));
class LPS:
def findLPSLength(self, st):
dp = [[None] * len(st) for _ in range(len(st))]
return self.findLPSLengthRecursive(dp, st, 0, len(st) - 1)
def findLPSLengthRecursive(self, dp, st, startIndex, endIndex):
if startIndex > endIndex:
return 0
if startIndex == endIndex:
return 1
if dp[startIndex][endIndex] is None:
if st[startIndex] == st[endIndex]:
dp[startIndex][endIndex] = 2 + self.findLPSLengthRecursive(dp, st, startIndex + 1, endIndex - 1)
else:
c1 = self.findLPSLengthRecursive(dp, st, startIndex + 1, endIndex)
c2 = self.findLPSLengthRecursive(dp, st, startIndex, endIndex - 1)
dp[startIndex][endIndex] = max(c1, c2)
return dp[startIndex][endIndex]
lps = LPS()
print(lps.findLPSLength("abdbca"))
print(lps.findLPSLength("cddpd"))
print(lps.findLPSLength("pqr"))
package main
import (
"fmt"
)
type LPS struct{}
func (lps *LPS) findLPSLength(st string) int {
dp := make([][]int, len(st))
for i := range dp {
dp[i] = make([]int, len(st))
}
return lps.findLPSLengthRecursive(dp, st, 0, len(st)-1)
}
func (lps *LPS) findLPSLengthRecursive(dp [][]int, st string, startIndex, endIndex int) int {
if startIndex > endIndex {
return 0
}
if startIndex == endIndex {
return 1
}
if dp[startIndex][endIndex] == 0 {
if st[startIndex] == st[endIndex] {
dp[startIndex][endIndex] = 2 + lps.findLPSLengthRecursive(dp, st, startIndex+1, endIndex-1)
} else {
c1 := lps.findLPSLengthRecursive(dp, st, startIndex+1, endIndex)
c2 := lps.findLPSLengthRecursive(dp, st, startIndex, endIndex-1)
dp[startIndex][endIndex] = max(c1, c2)
}
}
return dp[startIndex][endIndex]
}
func max(a, b int) int {
if a > b {
return a
}
return b
}
func main() {
lps := LPS{}
fmt.Println(lps.findLPSLength("abdbca"))
fmt.Println(lps.findLPSLength("cddpd"))
fmt.Println(lps.findLPSLength("pqr"))
}
自底向上
class LPS {
public int findLPSLength(String st) {
// dp[i][j]矩阵用于存储从索引i到索引j的最长回文子序列的长度
int[][] dp = new int[st.length()][st.length()];
// 每个只有一个元素的序列是一个长度为1的回文
for (int i = 0; i < st.length(); i++)
dp[i][i] = 1;
for (int startIndex = st.length() - 1; startIndex >= 0; startIndex--) {
for (int endIndex = startIndex + 1; endIndex < st.length(); endIndex++) {
// case 1: 开头和结尾的元素相同
if (st.charAt(startIndex) == st.charAt(endIndex)) {
dp[startIndex][endIndex] = 2 + dp[startIndex + 1][endIndex - 1];
} else { // case 2: 跳过在开头和结尾的元素
dp[startIndex][endIndex] = Math.max(dp[startIndex + 1][endIndex], dp[startIndex][endIndex - 1]);
}
}
}
return dp[0][st.length() - 1];
}
public static void main(String[] args) {
LPS lps = new LPS();
System.out.println(lps.findLPSLength("abdbca"));
System.out.println(lps.findLPSLength("cddpd"));
System.out.println(lps.findLPSLength("pqr"));
}
}
class LPS {
findLPSLength(st) {
const dp = Array(st.length)
.fill(0)
.map(() => Array(st.length).fill(0));
for (let i = 0; i < st.length; i++) {
dp[i][i] = 1;
}
for (let startIndex = st.length - 1; startIndex >= 0; startIndex--) {
for (let endIndex = startIndex + 1; endIndex < st.length; endIndex++) {
if (st[startIndex] === st[endIndex]) {
dp[startIndex][endIndex] = 2 + dp[startIndex + 1][endIndex - 1];
} else {
dp[startIndex][endIndex] = Math.max(dp[startIndex + 1][endIndex], dp[startIndex][endIndex - 1]);
}
}
}
return dp[0][st.length - 1];
}
}
const lps = new LPS();
console.log(lps.findLPSLength('abdbca'));
console.log(lps.findLPSLength('cddpd'));
console.log(lps.findLPSLength('pqr'));
class LPS:
def findLPSLength(self, st):
dp = [[0] * len(st) for _ in range(len(st))]
for i in range(len(st)):
dp[i][i] = 1
for startIndex in range(len(st) - 1, -1, -1):
for endIndex in range(startIndex + 1, len(st)):
if st[startIndex] == st[endIndex]:
dp[startIndex][endIndex] = 2 + dp[startIndex + 1][endIndex - 1]
else:
dp[startIndex][endIndex] = max(dp[startIndex + 1][endIndex], dp[startIndex][endIndex - 1])
return dp[0][len(st) - 1]
lps = LPS()
print(lps.findLPSLength("abdbca"))
print(lps.findLPSLength("cddpd"))
print(lps.findLPSLength("pqr"))
package main
import "fmt"
type LPS struct{}
func (lps *LPS) findLPSLength(st string) int {
dp := make([][]int, len(st))
for i := range dp {
dp[i] = make([]int, len(st))
}
for i := 0; i < len(st); i++ {
dp[i][i] = 1
}
for startIndex := len(st) - 1; startIndex >= 0; startIndex-- {
for endIndex := startIndex + 1; endIndex < len(st); endIndex++ {
if st[startIndex] == st[endIndex] {
dp[startIndex][endIndex] = 2 + dp[startIndex+1][endIndex-1]
} else {
dp[startIndex][endIndex] = max(dp[startIndex+1][endIndex], dp[startIndex][endIndex-1])
}
}
}
return dp[0][len(st)-1]
}
func max(a, b int) int {
if a > b {
return a
}
return b
}
func main() {
lps := &LPS{}
fmt.Println(lps.findLPSLength("abdbca"))
fmt.Println(lps.findLPSLength("cddpd"))
fmt.Println(lps.findLPSLength("pqr"))
}